请来答谢谢{4又1/5-3又1/2+1又3/4}÷345²-（-0.01²）÷11
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解决时间 2021-11-08 19:32
- 提问者网友：伴风望海
- 2021-11-08 08:58
请来答谢谢{4又1/5-3又1/2+1又3/4}÷345²-（-0.01²）÷11
最佳答案
- 五星知识达人网友：怙棘
- 2021-11-08 09:09
{4又1/5-3又1/2+1又3/4}÷345²-（-0.01²）÷11
={4.2-3.5+1.75}÷345²+0.0001÷11
=2.45÷345²+1/110000
=2.45÷119025+1/110000
≈0.00002058+0.000009091
=0.000011149
={4.2-3.5+1.75}÷345²+0.0001÷11
=2.45÷345²+1/110000
=2.45÷119025+1/110000
≈0.00002058+0.000009091
=0.000011149
全部回答
- 1楼网友：怀裏藏嬌
- 2021-11-08 10:03
{4又1/5-3又1/2+1又3/4}÷345²-（-0.01²）÷11
={4.2-3.5+1.75}÷345²+0.0001÷11
=2.45÷345²+1/110000
=2.45÷119025+1/110000
≈0.00002058+0.000009091
=0.0000
={4.2-3.5+1.75}÷345²+0.0001÷11
=2.45÷345²+1/110000
=2.45÷119025+1/110000
≈0.00002058+0.000009091
=0.0000
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