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hibernate 别名查询时保存[type.StringType] could not read column value from result set:

答案:1  悬赏:80  手机版
解决时间 2021-04-25 07:41
  • 提问者网友:寂寞梧桐
  • 2021-04-25 01:22
  select
        p.provinceName as name,
        count(s.id) as 'byrs',
        sum(if(s.employment is not null && s.employment<>'',
        1,
        0))+sum(if(s.graduate is not null && s.graduate<>'',
        1,
        0))+sum(if(s.studyAbroad is not null && s.studyAbroad<>'',
        1,
        0)) as 'jyrs',
        CAST(( sum(if(s.employment is not null && s.employment<>'',
        1,
        0))+sum(if(s.graduate is not null && s.graduate<>'',
        1,
        0))+sum(if(s.studyAbroad is not null && s.studyAbroad<>'',
        1,
        0)))/count(s.id) as decimal(38,
        3))*100 as 'jyl'
    from
        Student s
    inner join
        School c
            on s.school_id=c.id
    inner join
        Dictionary_Province p
            on c.province_id=p.id
    where
        s.isInside=0 
        and year(s.graduationTime)=2010
    group by
        p.provinceName

用mysql客户端可以查询,但是用hibernate查询的时候就保存!(老系统查询的时候就没有报错!)
最佳答案
  • 五星知识达人网友:山河有幸埋战骨
  • 2021-04-25 02:52

光给这一小段代码是很难什么东东来的.

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