c++ 泛型 模板继承问题

c++ 泛型 模板继承问题

。。。。。。。
VS2012，给你重新写一个。

#include
#include
#include

enum class Type {
ADD,
SUB
};

template
class Operator {
public:
void setX(const Op & x) {
_x = x;
}
void setY(const Op & y) {
_y = y;
}
virtual Op result() = 0;
virtual ~Operator() {}
public:
Op _x;
Op _y;
};

template
class Add : public Operator {
typedef Operator Base;
public:
Op result() override {
return Base::_x + Base::_y;
}
};

template
class Sub : public Operator {
typedef Operator Base;
public:
Op result() override {
return Base::_x - Base::_y;
}
};

class Factory {
public:
template
static Operator *create(Type type) {
switch(type) {
case Type::ADD:
return new Add;
case Type::SUB:
return new Sub;
default:
throw std::invalid_argument("Factory::create");
}
}
};

int main() {
Operator * op = Factory::create(Type::ADD);
op->setX(1);
op->setY(2);
std::cout << "add = " << op->result() << std::endl;
Operator *op2 = Factory::create(Type::SUB);
op2->setX(2);
op2->setY(1);
std::cout << "sub = " << op2->result() << std::endl;
system("pause");
}

std::auto_ptr CreateOperation(OPERTYPE aType) //差这个">" 吧
{
Operation *ptr = NULL;

无良啊，天杀的啊，无语啊........................

两个笔误，template
class OperationFacory
{
public:
std::auto_ptr> CreateOperation(OPERTYPE aType)//少了一个右尖括号
{
Operation *ptr = NULL;//Operation是泛型的，得带上
switch(aType)
{
case OPER_ADD:
ptr = new OperationAdd;
break;
case OPER_SUB:
ptr = new OperationSub;
break;
default:
ptr = NULL;
}
return std::auto_ptr>(ptr);
}
};

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