6x-6y-9x^2+18xy-9y^2-1
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解决时间 2021-03-10 08:18
- 提问者网友：杀生予夺
- 2021-03-09 14:33
分解因式
最佳答案
- 五星知识达人网友：鸽屿
- 2021-03-09 15:07
标准答案来了
6x-6y-9x^2+18xy-9y^2-1
=-9(x^2-2xy+y^2)+6(x-y)-1
=-9(x-y)^2+6(x-y)-1
=-[3(x-y)]^2+6(x-y)-1
=-{[3(x-y)]^2-2*[3(x-y)]*1+1^2}
=-[3(x-y)-1]^2
6x-6y-9x^2+18xy-9y^2-1
=-9(x^2-2xy+y^2)+6(x-y)-1
=-9(x-y)^2+6(x-y)-1
=-[3(x-y)]^2+6(x-y)-1
=-{[3(x-y)]^2-2*[3(x-y)]*1+1^2}
=-[3(x-y)-1]^2
全部回答
- 1楼网友：思契十里
- 2021-03-09 15:42
基本的思路就是应用两次完全平方公式：
6x-6y-9x^2+18xy-9y^2-1
=(-9x^2-9y^2+18xy)+(6x-6y)-1
=-9(x-y)^2+6(x-y)-1
=-3^2*(x-y)^2+6(x-y)-1
=-{3(x-y)}^2+2*3(x-y)-1
=-【{3(x-y)}^2-2*3(x-y)+1】^2
=-{3(x-y)-1}^2
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