957+792-(431+392)+39
(8)(998+379+158)-(997+378+157)
(9)9-0.9-0.09-0.009-0.0009
(10)41.2×8.1+11×1.25+537×0.19
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答案:2 悬赏:70 手机版
解决时间 2021-02-08 13:47
- 提问者网友:我没有何以琛的痴心不悔
- 2021-02-08 09:25
最佳答案
- 五星知识达人网友:第幾種人
- 2021-02-08 10:05
957+792-(431+392)+39
=957+792-431-392+39
=957+400-400-31+39
=957+8=965
(998+379+158)-(997+378+157)
=998-997+379-378+158-157
=1+1+1=3
9-0.9-0.09-0.009-0.0009
=9-1+0.1-0.1+0.01-0.01+0.001-0.001+0.0001
=8+0.0001=8.0001
41.2×8.1+11×1.25+537×0.19
=(42-0.8)*(8+0.1)+10*1.25+1.25+537*(0.2-0.01)
=42*8-6.4-0.08+4.8+12.5+1.25+107.4-5.37
=336-6.48+4.8+13.75+107.4-5.37
=450.1
=957+792-431-392+39
=957+400-400-31+39
=957+8=965
(998+379+158)-(997+378+157)
=998-997+379-378+158-157
=1+1+1=3
9-0.9-0.09-0.009-0.0009
=9-1+0.1-0.1+0.01-0.01+0.001-0.001+0.0001
=8+0.0001=8.0001
41.2×8.1+11×1.25+537×0.19
=(42-0.8)*(8+0.1)+10*1.25+1.25+537*(0.2-0.01)
=42*8-6.4-0.08+4.8+12.5+1.25+107.4-5.37
=336-6.48+4.8+13.75+107.4-5.37
=450.1
全部回答
- 1楼网友:归鹤鸣
- 2021-02-08 10:17
=(1-1/2^2)(1-1/3^2)……(1-1/2001^2)
=[(2/2)^2-(1/2)^2][(3/3)^2-(1/3)^2]......[(2001/2001)^2-(1/2001)^2]
=[(1/2)*(3/2)][(2/3)*(4/3)]......[(2000/2001)*(2002/2001)]
=(1/2)*(2002/2001)
=1001/2001
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