(x-1)(x-3)(x-4)(x-12)+5x^2=0解方程

(x-1)(x-3)(x-4)(x-12)+5x^2=0解方程

(x-1)(x-3)(x-4)(x-12)+5x^2=0
(x-1)(x-12)(x-3)(x-4)+5x^2=0
(x^2-13x+12)(x^2-7x+12)+5x^2=0
[(x^2-10x+12)-3x][(x^2-10x+12)+3x]+5x^2=0
(x^2-10x+12)^2-9x^2+5x^2=0
(x^2-10x+12)^2-4x^2=0
[(x^2-10x+12)-2x][(x^2-10x+12)+2x]=0
(x^2-12x+12)(x^2-8x+12)=0
(x^2-12x+12)(x-2)(x-6)=0
x1=2
x2=6
x^2-12x+12=0
x^2-12x=-12
x^2-12x+36=36-12
(x-6)^2=24
x-6=±2√6
x3=6+2√6
x4=6-2√6

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