f((x)=(1.5x)/(1+x^2)^2-0.65tan^-1 (1/x)+(0.65x)/(1+x^2)=0
请问这个式子怎么求?
要求用Newton-Raphson method with starting point x1=0.0 and the convergence criterion є=10^(-5)
最少要告诉我tan^-1 (1/x)得多少?(代数)例如:x=0, x=1, x=2, x=-1
f((x)=(1.5x)/(1+x^2)^2-0.65tan^-1 (1/x)+(0.65x)/(1+x^2)=0
请问这个式子怎么求?
要求用Newton-Raphson method with starting point x1=0.0 and the convergence criterion є=10^(-5)
最少要告诉我tan^-1 (1/x)得多少?(代数)例如:x=0, x=1, x=2, x=-1
tan^{-1}就是反正切atan或者写成arctan嘛
arctan(1/0)=π/2
arctan(1/1)=π/4
arctan(1/2)=π/6
arctan(1/(-1))=-π/4