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数据转换错误java.lang.numberformatexception null java.lang.integer

答案:1  悬赏:0  手机版
解决时间 2021-08-15 17:18
  • 提问者网友:临风不自傲
  • 2021-08-14 22:09
数据转换错误java.lang.numberformatexception null java.lang.integer.parseint integer.java
org.apache.jasper.JasperException:An exception occurred processing JSP page /reply.jsp at line 6
3:
4:
8:
9:
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:515)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:426)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
root cause
java.lang.NumberFormatException:null
java.lang.Integer.parseInt(Integer.java:415)
java.lang.Integer.parseInt(Integer.java:497)
org.apache.jsp.reply_jsp._jspService(reply_jsp.java:57)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
note The full stack trace of the root cause is available in the Apache Tomcat/6.0.10 logs.
最佳答案
  • 五星知识达人网友:逐風
  • 2021-08-14 22:46

错误出现原因:数字格式化异常,如果id、rootId 是null,你的代码是要把null转换成int类型,就会出错,可以修改代码如下:
int id = 0;
int rootId = 0;
if(request.getParameter(id) != null && !.equals(request.getParameter(id))) {
id = Integer.parseInt(request.getParameter(id));
}
if(request.getParameter(rootId) != null && !.equals(request.getParameter(rootId))) {
rootId = Integer.parseInt(request.getParameter(rootId));
}


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