dedecms如何把这个导航做成循环导航？求解

<input type="hidden" value="1" id="hidTypeId" />

<div id="menu" class="menu">

<ul class="mwrap">

<li class="mli">

<a href="{dede:global.cfg_basehost/}" class="mlink" id="topMenu1">

<span class="mico mico_home"><span class="micoi"></span></span>

<span class="mname">首页</span>

</a>

</li>

<li class="mli">

<a href="[field:typelink/]" class="mlink curr" id="topMenu2">

<span class="mico mico_about"><span class="micoi"></span></span>

<span class="mname">[field:typename/]</span>

</a>

</li>

<li class="mli">

<a href="[field:typelink/]" class="mlink" id="topMenu3">

<span class="mico mico_service"><span class="micoi"></span></span>

<span class="mname">[field:typename/]</span>

</a>

</li>

<li class="mli">

<a href="[field:typelink/]" class="mlink" id="topMenu4">

<span class="mico mico_case"><span class="micoi"></span></span>

<span class="mname">[field:typename/]</span>

</a>

</li>

<li class="mli">

<a href="[field:typelink/]" class="mlink" id="topMenu5">

<span class="mico mico_news"><span class="micoi"></span></span>

<span class="mname">[field:typename/]</span>

</a>

</li>

<li class="mli">

<a href="[field:typelink/]" class="mlink" id="topMenu6">

<span class="mico mico_contact"><span class="micoi"></span></span>

<span class="mname">[field:typename/]</span>

</a>

</li>

</ul>

<div class="mshadow"></div>

</div>

</div>

<script type="text/javascript">

var typeid= document.getElementById("hidTypeId").value;

for(var i = 1 ;i <= 6;i++)

{

if(i == typeid){

document.getElementById("topMenu" + i).className="mlink curr";

}else

{

document.getElementById("topMenu" + i).className="mlink";

}

}

</script>

arclist  从0开始 [field:global name=autoindex
runphp="yes"]@me=@me-1;[/field:global]
channel  从1开始 [field:global name=autoindex
runphp="yes"]@me=@me+1;[/field:global][field:typename/]
channelartlist  从0开始 {dede:global name=itemindex
runphp='yes'}@me=@me-1;{/dede:global}你的那个id1 2  3 看下是在哪个的标签里面用对应的即可

搜一下：dedecms如何把这个导航做成循环导航？求解

如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！

点此我要举报以上问答信息