分解因式：（xy-1)²+（x+y-2）（x+y-2xy）
答案:3 悬赏:20 手机版
解决时间 2021-03-23 05:06
- 提问者网友：战魂
- 2021-03-23 01:14
哪位大神来解这道题！！赶时间！！
最佳答案
- 五星知识达人网友：七十二街
- 2021-03-23 01:27
(xy-1)²+(x+y-2)(x+y-2xy)
=（xy)²-2xy+1+(x+y)²-2(x+y)-2xy(x+y)+4xy
=(xy+1))²+(x+y)²-2(x+y)(xy+1)
=(xy+1-x-y)²
=（xy)²-2xy+1+(x+y)²-2(x+y)-2xy(x+y)+4xy
=(xy+1))²+(x+y)²-2(x+y)(xy+1)
=(xy+1-x-y)²
全部回答
- 1楼网友：归鹤鸣
- 2021-03-23 02:52
解：原式=（x+y)^2-2(xy+1)(x+y)+4xy+(xy)^2-2xy+1
==（x+y)^2-2(xy+1)(x+y)+(xy+1)^2
==(x+y-xy-1)^2
- 2楼网友：轻熟杀无赦
- 2021-03-23 01:38
(xy-1)²+(x+y-2)(x+y-2xy)
=x²y²-2xy+1+(x+y)²-2xy(x+y)-2(x+y)+4xy
=x²y²+2xy+1+(x+y)²-2xy(x+y)-2(x+y)
=(xy+1)²+(x+y)²-2(x+y)(xy+1)
=[(xy+1)-(x+y)]²
=(xy-x-y+1)²
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