[(x-1)/(x+2)]/[(x^2-2x+1)/(x^2-4)]+[1/(x-1)]
答案:2 悬赏:20 手机版
解决时间 2021-02-27 03:37
- 提问者网友：捧腹剧
- 2021-02-26 22:01
[(x-1)/(x+2)]/[(x^2-2x+1)/(x^2-4)]+[1/(x-1)]
最佳答案
- 五星知识达人网友：猎心人
- 2021-02-26 22:36
[(x-1)/(x+2)]/[(x^2-2x+1)/(x^2-4)]+[1/(x-1)]
=(x-1)/(x+2)*[(x+2)(x-2)]/(x-1)²+1/(x-1)
=(x-2)/(x-1)+1/(x-1)
=(x-1)/(x-1)
=1
=(x-1)/(x+2)*[(x+2)(x-2)]/(x-1)²+1/(x-1)
=(x-2)/(x-1)+1/(x-1)
=(x-1)/(x-1)
=1
全部回答
- 1楼网友：舊物识亽
- 2021-02-27 00:09
由f(x+1)=x^2-4，知a1=f(x-1)=（x-2)^2-4，a3=f(x)=（x-1）^2-4 又由2a2=a1+a3,可解的：x=0 x=3 1、当x=0时，a1=0,
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