2(x-3)²=x²-9 怎么用分解因式法解

2(x-3)²=x²-9 怎么用分解因式法解

①2(x-3)²=x²-9
2(x-3)²-(x²-9)=0
2(x-3)²-(x+3)(x-3)=0
(x-3)(2x-6-x-3)=0
(x-3)(x-9)=0
x=3或x=9

②9(2x+3)²-4(2x-5)²=0
(6x+9)²-(4x-10)²=0
(6x+9+4x-10)(6x+9-4x+10)=0
x=1/10或x=-19/2

③把右边移到左边，做法和第二题差不多
答案是x=-7/4或x=-11/2

1. 2(x-3)²=x²-9
x²-9-2(x-3)²=0
(x+3)(x-3)-2(x-3)²=0
(x-3)(9-x)=0
X1=3,X2=9
2. 9(2x+3)²-4(2x-5)²=0
(3(2x+3)+2(2x-5))(3(2x+3)-2(2x-5))=0
(6x+9-4x+10)(6x+9+4x-10)=0
(2x+19)(10x-1)=0
X1=-19/2,X2=1/10
3. (x-2)²=9(x+3)²
(x-2)²-9(x+3)²=0
((x-2)-3(x+3))((x-2)+3(x+3))=0
-(4x+7)(2x+11)=0
X1=-7/4,X2=-11/2

2(x-3)²=x²-9
2(x-3)²-x²-9＝0
2（x-3）（x-3）-(x+3)(x-3)=0
(2x-6-x-3)(x-3)=0
(x-9)(x-3)=0
x1=9 x2=3
9(2x+3)²-4(2x-5)²=0
(6x+9)²-(4x-10)²=0
(6x+9+4x-10)(6x+9-4x+10)=0
(10x-1)(2x+19)=0
x1=1/10x2=-19/2
(x-2)²=9(x+3)²=0
(x-2)²-9(x+3)²=0
(x-2)²-(3x+9)²=0
(x-2+3x+9)(x-2-3x-9)=0
(4x+7)(-2x-11)=0
x1=-7/4x2=-11/2
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